Errata

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The errata list is a list of errors and their corrections that were found after the product was released.

The following errata were submitted by our customers and have not yet been approved or disproved by the author or editor. They solely represent the opinion of the customer.

Color Key: Serious Technical Mistake Minor Technical Mistake Language or formatting error Typo Question



Version Location Description Submitted By
Printed Page 110-111
on p. 110, last code example; on p. 111, first code example

mel is used as the name of the dictionary being created. as 'mel' is used as data
content in the previous example (second code sample, p. 110), this strikes me as
distracting from the intent, that this example is very similar to the previous one
rather than a subdictionary of sorts, which could be inferred (confusingly) from the
example as it is.

 Anonymous 
Printed Page 122
4th line of first example

the output from the example:
>>> L1 = [1, ('a', 3)]
>>> L2 = [1, ('a', 3)]
>>> L1 < L2, L1 == L2, L1 > L2

should be (0, 1, 0) instead of (0, 0, 1), since L1 and L2 are equivalent lists.

 Anonymous 
Printed Page 472
4th paragraph, line 5 (code sample)

start,stop = stop, start + struct.calcsize('B'*num_bytes)

should be:

start,stop = stop, stop + struct.calcsize('B'*num_bytes)

...in order to advance the slice to the next piece of data.

 Anonymous 
Printed Page 544
Under the section of dictionaries

Answer key in the book for D[(1,2,3)]=4
>>>D
{'w':0, 'z':3 'y':2, (1,2,3):4, 'x':1)
The answer key is incorrect.
It should be.
>>> D[(1,2,3)]=4
>>> D
{'y': 2, 'x': 1, 'z': 3, 'w': 0, (1, 2, 3): 4}

Using Python version 2.4.4

 Anonymous 
Printed Page 568
line 5 from bottom in code

change:
if p[start:indexpepper].strip()
to
if p[start+lenword:indexpepper].strip()

 Anonymous