Head First Statistics Unconfirmed Errata

Errata

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The errata list is a list of errors and their corrections that were found after the product was released.

The following errata were submitted by our customers and have not yet been approved or disproved by the author or editor. They solely represent the opinion of the customer.

Color Key: Serious Technical Mistake Minor Technical Mistake Language or formatting error Typo Question

Version	Location	Description	Submitted By
Printed	Page 8 4th paragraph	Typo error - should be "showing" and NOT "showingg".	Anonymous
Printed	Page 116 Solution for player 3	In the key to the exercise "Be the Coach Solution", the mean of 11 listed for Player 3 is inaccurate. It should be 10 (as indicated in the exercise introduction) : 2(3)+6+2(7)+3(10)+11+13+30 110 ___________________________ = _____ = 10 11 11 The variance calculation should be corrected accordingly: 18+36+98+300+121+169+900 ________________________ -100 = 64.2 10 Hence the corrected value for the Standard Deviation for Player 3 is 8.01 (the square root of 64.2)which is slightly higher than the 7.02 reported in the book.	Yvan Bamps
Printed	Page 154 Left comment next to Venn diagram	Key to exercise lists 50 as the total number of sport lovers, it is 60. 16 + 16+ 28 =60	Yvan Bamps
Printed	Page 178 In the second "Vital Statistics"	The text says "n events A1 to An", the formula uses A and A'. The formula should use Σ (Sigma), or the text should say "two mutualy exclusive and exhaustive events A and A'".	Benjamin Poulain
Printed	Page 179 Last question: "How useful is Bayes Theorem in real life	The question is not written in bold.	Benjamin Poulain
Safari Books Online	272 very last calculation on page	It says "We can add these probabilities because they're independent." I think it should say "We can add these probabilities because they're mutually exclusive."	Kathy W.
Printed	Page 293 bottom of the page	3!/(3-1)0.250.5625 OK 6/2 * 0.0625*0.75 ????	Anonymous
Printed	Page 313 Combine Poisson Variables section	In order for the following relations to be true: P(X+Y)=P(X)+P(Y) E(X+Y)=E(X)+E(Y) X+Y~Po(lambda_x+lambda_y) shouldn't be required that the two variables be 'mutally exclusive' too?	Anonymous
Printed	Page 313 First equation on page	The probability for X and Y is listed as: P(X + Y) = P(X) + P(Y) Shouldn't this be: P(X + Y) = P(X) * P(Y) I understand that lambdaX + lambdaY = 5.7 Also, P(X=0) for lambda = 3.4 is 0.033 and P(Y=0) for lambda = 2.3 is 0.100 Thus, P(X=0) * P(Y=0) = 0.003, which matches P(X+Y=0) when lambda is 5.7, which is also 0.003 (as on p314).	mudphone
Safari Books Online	409 1st column, 1st and 2nd rows	Under both "X+Y" and "X-Y", the "N" for normal distribution is missing in Y ~ N ( mu_y , sigma^2_y )	Kathy Wolf
Safari Books Online	411 next to last row, last column	In the last column, under "Condition" it lists npq > 5 as the 2nd condition, when it should just be nq > 5.	Kathy Wolf
Safari Books Online	466 2nd paragraph of middle column under "there are no dumb questions"	It says "The expectation of the sampling population of proportions..." I believe it should say "The expectation of the sampling distribution of proportions..."	Anonymous
Safari Books Online	507 Answer to last question in first column	The answer is about the difference between the terms confidence level and confidence interval. The first sentence should read "The confidence level is the probability that your statistic is contained within the confidence interval," instead of "the confidence interval..."	Kathy Wolf
Printed	Page 511 2nd paragraph	The expectation of X bar is mu, and the standard deviation is sigma/n it should be sigma/sqrt(n)	Anonymous
Printed	Page 513 Using t-distribution probability tables	The first graphic on the page shows the two tails, measuring 0.025 each. Then the next graphic shows the single tail used to find the value of t, which is great - and implies that for our data p=0.025. In the first paragraph in the "Using t-distribution probability tables" you state that p=0.0025. What follows in an example, but for the example you use v=7 and p=0.05. This is a little confusing. I think most people will wonder if our p=0.025 is related to this new p=0.05. Since the first graphic shows two tails, this example might mean that you multiply the p times 2. In future editions I would explain the one- and two-tailed difference. I would change the example to use a p that is wildly different than 0.025 and 0.05. This will allow the reader to clearly understand that the lookup value is different from the current example (which he/she will have to look up for the following page's excercise).	Anonymous
Safari Books Online	515 or 518 Table at bottom of 515, first question on 518	In the table at the bottom of p. 515, it says that one of the conditions for using the t-distribution is that the population distribution is normal _or_ non-normal, but in the answer to the first question on p. 518, it doesn't mention being able to use it when the population is non-normal. I'm not sure which is right.	Kathy Wolf
Safari Books Online	590 Last table	In the row corresponding to wins from Croupier B, the (O-E) part wasn't squared. So it should read, (49-43.32)^2 / 43.32 = 32.2624 / 43.32 = .745	Kathy Wolf
Safari Books Online	638-639 Exercise Solution	I know this has already been mentioned in the errata, but in case, like me, you didn't notice the error until you had done the whole exercise already with the (original) data set on p. 636: n=9 xbar=5 ybar=10.06 b=-1.85 a=19.31 So y=19.31-1.85x r=-.92 If Swindler exposes Captain Amazing to radiation for 5 minutes, we would expect Captain Amazing to be able to lift 10.06 tons.	Kathy Wolf