Errata for Learning Visual Basic .NET
Submit your own errata for this product.
The errata list is a list of errors and their corrections that were found after the product was released. If the error was corrected in a later version or reprint the date of the correction will be displayed in the column titled "Date Corrected".
The following errata were submitted by our customers and approved as valid errors by the author or editor.
Color Key: Serious Technical Mistake Minor Technical Mistake Language or formatting error Typo Question Note Update
| Version |
Location |
Description |
Submitted By |
Date Submitted |
Date Corrected |
| Printed |
Page 38
IN PRINT: Example 5-1, fourth and sixth lines |
"Console.WriteLine..."
SHOULD BE:
"System.Console.WriteLine..."
|
Anonymous |
|
|
| Printed |
Page 48
first line |
Chapter 7 describes branching in detail
should be
Chapter 6 describes branching in detail
|
Anonymous |
|
|
| Printed |
Page 92
Ex. 8-3 |
Change the member variable Date to myDate throughout the program -- Date is a keyword.
|
Anonymous |
|
|
| Printed |
Page 96
Dim Command in Constructor paragraph |
"Dim timeObject as New Time();" ends with a semicolon. The semicolon should be
removed.
|
Anonymous |
|
|
| Printed |
Page 109
Line 16 |
Date = dt.Date
Should be:
Date = dt.Day
|
Anonymous |
|
|
| Printed |
Page 158
|
The syntax shown for defining an interface refers to access-modifiers. No access
modifiers are allowed except shadows. Shadows refers to the ability to have an
element in a derived class with the same name as an element in the base class,
which hides the element in the base class.
|
Anonymous |
|
|
| Printed |
Page 184
Code snippet just above "Accessing Array Elements" heading |
For i = 0 to empArray.Length -1
empArray(i) = New Employee(i + 5)
i = i + 1
Next
should be:
For i = 0 to empArray.Length -1
empArray(i) = New Employee(i + 5)
Next
(remove the line "i = i + 1")
|
Anonymous |
|
|
| Printed |
Page 257
Class Tester, Run method |
Dim id as Integer = 1 produces the following output:
2: One
3: Two
4: Three
5: Liberty
6: Associates
7: Inc.
should be
Dim id as Integer = 0 to produces output:
1: One
2: Two
3: Three
4: Liberty
5: Associates
6: Inc.
|
Anonymous |
|
|
