The errata list is a list of errors and their corrections that were found after the product was released. If the error was corrected in a later version or reprint the date of the correction will be displayed in the column titled "Date Corrected".
The following errata were submitted by our customers and approved as valid errors by the author or editor.
| Version |
Location |
Description |
Submitted By |
Date submitted |
Date corrected |
| Printed |
Page 10
First bullet item |
Bullet item states "The current into the collector, divided by the cutting into the base..."
Should read "The current into the collector, divided by the current into the base..."
|
James Floyd Kelly |
May 20, 2014 |
May 23, 2014 |
| Printed |
Page 12
Figure 2-8 |
Where indication of the meter connection is, it states, "Meter measures the voltage at the collector". I think this should be "...at the emitter".
Regards,
L.K. R.
Note from the Author or Editor:
The schematic in Figure 2-8 has been revised appropriately. |
Anonymous |
Jan 10, 2016 |
Aug 05, 2016 |
| Printed |
Page 18
Figure 3-3 |
In Figure 3-3 a photograph of a circuit is shown. I assume that the two twisted yellow cables that leave the breadboard are connected to the loudspeaker that is partially visible on the right. One of the yellow cables is connected to the 10 uF capacitor. The other yellow cable is connected to the 5VDC "+" rail, but I think it should be connected to the Ground "-" rail. Just like the schematic in Figure 3-2 shows.
Note from the Author or Editor:
Unfortunately it is not possible to rebuild and rephotograph the breadboarded circuit at this time, but it will work the way it has been photographed. Change the figure caption to this:
A breadboarded version of the phototransistor test circuit using a 555 timer. The phototransistor is the transparent object at front-center. The yellow wires power the speaker. The schematic in the previous figure shows the speaker connected through a 100-ohm resistor to negative ground, but a high-impedance speaker will also work when connected to the positive side of the power supply, as the 555 timer will sink or source current. |
Pepijn Koopman |
Sep 27, 2015 |
Dec 18, 2015 |
| Printed |
Page 50
Figure 7-12 & Figure 7-13 |
Printed version 2014-4-25 on Page 50 in Figures 7-12 & 7-13
My understanding is figure 7-12 and figure 7-13 are the schematic and breadboard version of the same circuit.
In figure 7-12 there are 1K resistors shown on the base lead of both 2N2222 transistors where they connect to the number 3 pin of the 555 timers.
In figure 7-13 the base of those 2N2222 transistors appear to go directly to the 555 timers without a resistor.
Note from the Author or Editor:
The reader is correct, but unfortunately it is not possible to rebuild and rephotograph the breadboarded circuit at this time. The circuit will work without the 1K resistors that are shown in the schematic. |
Anonymous |
Jan 14, 2015 |
|
| Printed |
Page 82
Under "Is It Right?" 1st and 2nd paragraphs |
The equation for gain appears to be incorrect. On page 82, the equation for gain is Gain = 1 + (G/F), but I think it should be Gain = 1 + (F/G) as was stated on page 75.
In the following paragraph, the text mistakenly states that the value of the "G" resistor is 1M and the "F" resistor is 10K, when in Figure 11-4 those values are reversed.
Fortunately, both errors cancel each other and the correct value is reached!
Note from the Author or Editor:
Page 82, first column, last line. The formula should be rewritten like this:
Gain = 1 + ( F / G )
Also on page 82, second column, first line, letter "G" (in quotes) should be replaced with letter "F" (also in quotes), while on the second line, letter "F" (in quotes) should be replaced with letter "G" (also in quotes). |
Vida John |
Apr 21, 2016 |
Aug 05, 2016 |
| Printed |
Page 93
first column, second paragraph. |
"...make sure that the 1M potentiometer is providing maximum resistance between the OP-AMP output and the non-inverting input..."
Inverting should replace non-inverting.
On figure 13-1 the 1M potentiometer is connected to the inverting input (pin 2).
LM741 = OP-AMP = negative feedback = inverting input.
Note from the Author or Editor:
Page 93, left column, 7th line, hyphenated word "noninverting" should be replaced with word "inverting." |
TEILHAC |
May 05, 2016 |
Aug 05, 2016 |
| Printed |
Page 102
Figure 14-1 |
There should be a 10K resistor from pin 2 of the second 555 timer to +9VDC. Without this pull-up resistor, the operation is erratic.
Note from the Author or Editor:
The reader is correct. This resistor was omitted from the schematic by error. A new version of the schematic will be supplied. |
Lloyd K |
Jul 10, 2014 |
Dec 18, 2015 |
| Printed |
Page 200
Figure 25-1 |
Printed version 2014-04-25 on page 200 in figure 25-1
As the other person said:
On 74HC4514 Pin1 to +5v, Pin2 to Bin input 1, Pin3 to Bin input 2.
Note from the Author or Editor:
Revised schematic will be provided to publisher. |
Anonymous |
Jan 22, 2015 |
Dec 18, 2015 |
| Printed |
Page 232
Figure 28-9 and following text |
Pin 9 is shown as optionally connected to ground (and described as such in the text below). That doesn't make sense and creates a shortcut via internal diodes.
It should be optionally connected to +voltage if being used with inductive loads.
Note that I'm an amateur and double check please.
Best regards
Robert
Note from the Author or Editor:
The reader is correct. On page 232 please delete the second paragraph and substitute this text:
A negative ground connection must be made on pin 8 of the ULN2003 to sink the current. A positive connection on pin 9 is necessary when powering an inductive load such as a relay coil, which can create "back EMF." The positive source must be the same source that is powering the coil. Diodes inside the ULN2003 should divert transients to protect the chip if the positive connection is included. For a circuit that is only driving light bars, the connection is not required.
|
Robert Lander |
Jun 01, 2017 |
Nov 24, 2017 |
| PDF |
Page 250
2 nd |
Here is a sentence : A sensor is most easily tested with the same kind of rectangular bar magnet that you used to in- vestigate a reed switch in Experiment 28.
It is incorrect claim. Bar magnet was first used in Experiment 29. There are no any magnets or reed switches in experiment 28.
Note from the Author or Editor:
Change text to:
A sensor is most easily tested with the same kind of neodymium magnet described in Experiment 28. It can be a cylindrical or bar-shaped magnet. |
Arman Januzak |
Oct 17, 2015 |
Dec 18, 2015 |
| Printed |
Page 261
Second paragraph under Phototransistor Test section |
The voltage when the card is removed/inserted is reversed to what the paragraph actually states.
Currently says:
.. a high voltage that exceeds 4.5VDC when the card is removed, and a low voltage that is less than 0.5VDC when the card is inserted.
Should say:
.. a high voltage that exceeds 4.5VDC when the card is inserted, and a low voltage that is less than 0.5VDC when the card is removed.
Note from the Author or Editor:
Penultimate paragraph on page 261, please substitute this text for the sentence that begins "By adjusting...."
By adjusting the trimmer, you should be able to achieve a a high voltage that exceeds 4.5VDC when the card is inserted, and a low voltage that is less than 0.5VDC when the card is removed. |
Anonymous |
Jun 28, 2015 |
Dec 18, 2015 |
| Printed, PDF, ePub, Mobi, , Other Digital Version |
Page 327
Paragraph under the subheading "The Kit Option" |
Please change:
Component kits will be available for this book.
They are compiled on the same basis as if you
were doing Moderate Shopping as defined
above. For information, see http://www.make
rshed.com.
To:
Component kits are available for this book. Because the suppliers of
kits may change from time to time, I have set up a web site that will
refer you to the current sources. Please see http://www.plattkits.com
for information. In case of difficulties, send email to
make.electronics@gmail.com.
|
Brian Jepson |
Jan 25, 2016 |
Aug 05, 2016 |
| Printed |
Page 347
Experiment 23 list |
The wrong number of switches is listed in the parts list for Experiment 23. This experiment requires at least 9 4PDT switches.
Note from the Author or Editor:
On page 347, bottom right, parts list for experiment 23, instead of 4PDT pushbutton (6) please substitute:
4PDT pushbutton (9)
|
Anonymous |
Jul 25, 2014 |
Dec 18, 2015 |